Question

Найдите f'(п), если: в) f (x) = 2sinx-1;​

Answer 1

Ответ:

f(x) = 2sin(x) - 1

f^ prime (x) = derivative of 2sin(x) - 1 for x

f^ prime (x) = derivative of 2sin(x) for x - derivative of 1 for x

f^ prime (x) = 2cos(x) + 0

f^ prime (x) = 2cos(x)