Question

Розв'яжіть рiвняння 36x3+12х2+x=0​

Answer 1

$\displaystyle\bf\\36x^{3}+12x^{2} +x=0\\\\x\cdot(36x^{2} +12x+1)=0\\\\36x^{2} +12x+1=0\\\\D=12^{2} -4\cdot 36\cdot 1=144-144=0\\\\x=\frac{-12}{72} =-\frac{1}{6} \\\\36x^{2} +12x+1=36\cdot\Big(x+\frac{1}{6} \Big)^{2} \\\\\\x\cdot 36\cdot\Big(x+\frac{1}{6} \Big)^{2} =0\\\\\boxed{x_{1} =0}\\\\x+\frac{1}{6} =0\\\\\boxed{x_{2} =-\frac{1}{6}} \\\\\\Otvet \ : \ 0 \ ; \ -\frac{1}{6}$

Answer 2

Ответ:

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Объяснение: