Question

Розкласти на множники многочлен 27k³-d³​

Answer 1

Объяснение:

$27 {k}^{3} - {d}^{3} = (3k - d)(9 {k}^{2} + 3kd + {d}^{2} )$

Answer 2

$27k^{3}-d^{3}\\ 3^{3}k^{3}-d^{3} \\ (3k)^{3} -d^{3}\\ (3k-d) ((3k)^{2} +3kd+d^{2})\\(3k-d) (9k^{2} +3kd+d^{2})\\(3k-d) (9k^{2} +3dk+d^{2})$