Question

вычислите на питоне
s=1/2+1/4+1/6+1/8...1/(2^N)

Answer 1

Ответ:

Объяснение:

s = 1/2

   1/4 + 1/6 + 1/8 + ... + 1/(2^N)

Python code: N = int(input('Please enter N: ')) s = 0

for i in range(1, N+1): s += 1/(2**i)

print('The sum is:', s)