Question

допоможіть будь ласка ​

Answer 1

1. використовуєм формули скороченого множення

$(8m+3y)(8m-3y)= (8m)^{2}-(3y)^{2}=64m^{2}-9y^{2}$

$(0,3p^{3}+0,2q^{4})(0,3p^{3}-0,2q^{4})= (0,3p^{3})^{2}-(0,2q^{4})^{2}= 0,09p^{6}-0,04q^{8}$

$(1,3a^{11}+\frac{2}{9}b^{3})(\frac{2}{9}b^{3}-1,3a^{11})= (\frac{2}{9}b^{3})^{2} - (1,3a^{11})^{2}= \frac{4}{81}b^{6}-1,69a^{22}$

$(0,4a-5b)^{2}= (0,4a)^{2} -2*0,4a*5b +(5b)^{2}= 0,16a^{2} -4ab+25b^{2}$

$(6pq^{2}+qp^{2})^{2}= (6pq^{2} )^{2}+2*6pq^{2}*qp^{2}+(qp^{2})^{2}=36p^{2}q^{4}+12p^{3}q^{3}+q^{2}p^{4}$

$(2x^{4}+5x^{3}b^{5})^{2} = (2x^{4})^{2} +2*2x^{4} *5x^{3} b^{5} +(5x^{3} b^{5} )^{2} =4x^{8}+20x^{7}b^{5} +25x^{6} b^{10}$

$(x+3)(x^{2} -3x+9)=x^{3} +3^{3} =x^{3} +27$

2.

$7x^{2} -28=7(x^{2} -4)$

$4m^{2} n^{4} -64m^{2} p^{2} =4m^{2} (n^{4} -16p^{2} )$

$-4+169x^{4}y^{18} =-(4-169x^{4}y^{18} )$