Question

(4(x + 3) > 3(x+1)-9 8(x-2) ≤4(x+2) (x2-4 1x 3(x + 1)-9 8(x-2) ≤4(x+2)​

Answer 1

Ответ:

2(3x+1)- x ≤ 3(x+4).

6x + 2 x ≤ 3x + 12,

5x+23x + 12,

7x+4x-86 +18x,

11x 86+18x,

5x-3x12-2,

11x-18x6+8,

2x ≤ 10,

-7x > 14.

X ≤5,

x <- 2,

x€ (-;-2);

XE (-; 5]

3) 2(x-1)-3(x+2) < 6(1 + x),

2) 7x+4(x-2) > 6(1+3x).

4) 7(y+3)-2(y+2) ≥ 2(5y +

2x-2-3x-6<6+6x, -x-8< 6+ 6x,

5y + 17 ≥ 10y + 2,

-x-6x < 6+ 8,

5y-10y 22-17,

-7x < 14,

-5y-15,

y≤3,

x = (-2:+)

y€ (-3).

7y+21-2y-4≥ 10y + 2