Question

сократить дробь:
sin5a cos3a+sin3a cos5a / sin10a+sin6a

Answer 1

$sin5a*cos3a+sin3a*cos5a=sin(5a+3a)=sin(8a)\ frac{sin8a}{sin10a+sin6a}\ sin10a+sin6a=2sin8acos2a\ frac{sin8a}{2sin8a*cos2a}=frac{1}{2cos2a}$