Question

розкласти на множники 81a²+36ac+4c²​

Answer 1

81a²+36ac+4c²=(9а)²+9а•2с•2+(2с)²=(9а+2с)²

Answer 2

81a² + 36ac + 4c² =
= 9²a² + 2 * 9a * 2c + 2²c² =

= (9a)² + 2 * 9a * 2c + (2c)² =

= (9a + 2c)²