Question

(2x^2+3x-35)/x+5=x^2+6x-12

Answer 1

$frac{2x^2+3x-35}{x+5}=x^2+6x-12\ 2x^2+3x-35=(x^2+6x-12)(x+5)\ 2x^2+3x-35=x^3+6x^2-12x+5x^2+30x-60\ 2x^2+3x-35=x^3+11x^2+18x-60\ x^3+9x^2+15x-25=0\ (x-1)(x+5)^2=0\ x=1\ x=-5$