Question

4x^2 = 4x - 1
Решите пж

Answer 1

Ответ: x = 4

4x^2 = 4x - 1

4x^2 - 4x + 1 = 0

D = b^2 - 4ac

D = (-4)^2 - 4 * 4 * 1

D = 16 - 16

D = 0

x= (-b + √D)/(2a)

x = 4 + 0

x = 4

Answer 2

Ответ:

D = b^2 - 4ac

D = (-4)^2 - 4 * 4 * 1

D = 16 - 16

D = 0

x= (-b + √D)/(2a)

x = 4 + 0

x = 4