Question

х^3-7х^2-3х+21=

(4х-7у)^3+8у(4х-7у)^2=

(4-3x)^2-49=
ПОМОГИТЕ ПОЖАЛУЙСТА!!!!

Answer 1

Объяснение:

${x}^{3} - 7 {x}^{2} - 3x + 21 = ( {x}^{3} - 7 {x}^{2} ) - (3x - 21) = {x}^{2} (x - 7) - 3(x - 7) = ( {x}^{2} - 3)(x - 7) = (x - \sqrt{3} )(x + \sqrt{3} )(x - 7)$

$(4x - 7y {)}^{3} + 8y(4x - 7y {)}^{2} = (4x - 7y {)}^{2} (4x - 7y + 8y) = (4x - 7y {)}^{2} (4x + y)$

$(4 - 3x {)}^{2} - 49 = (4 - 3x - 7)(4 - 3x + 7) = ( - 3 - 3x)(11 - 3x) = - 3(1 + x)(11 - 3x)$