Question

СРОЧНО ПЖ
СТАВЛЮ 75​

Answer 1

$\displaystyle\bf\\1)\\\\b_{1} =3\\\\b{2} =12\\\\\\b_{2} =b_{1} \cdot q\\\\\\q=\frac{b_{2} }{b_{1} } =\frac{12}{3} =4\\\\\\\boxed{q=4}\\\\\\2)\\\\b_{n}=3^{n+1} \\\\b_{1}=3^{1+1} =3^{2}=9\\\\b_{2}=3^{2+1} =3^{3} =27\\\\q=\frac{b_{2} }{b_{1} }=\frac{27}{3}=9\\\\\boxed{q=9}$