Question

Пж, с объяснением. Срочно! Алгебра 8​

Answer 1

$\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}-\sqrt{5}}-\sqrt{35}=\frac{\left ( \sqrt{7}+\sqrt{5} \right )\left ( \sqrt{7}-\sqrt{5} \right )}{\left ( \sqrt{7}-\sqrt{5} \right )^2}-\sqrt{35}=\frac{7-5}{7-2\sqrt{35}+5}-\sqrt{35}=\frac{2}{12-2\sqrt{35}}-\sqrt{35}=\frac{1}{6-\sqrt{35}}-\sqrt{35}\\\frac{1-\sqrt{35}\left ( 6-\sqrt{35} \right )}{6-\sqrt{35}}=\frac{1-6\sqrt{35}+35}{6-\sqrt{35}}=\frac{36-6\sqrt{35}}{6-\sqrt{35}}=\frac{6\left ( 6-\sqrt{35} \right )}{6-\sqrt{35}}=6$