Question

(4p-1)(16p^2+4p+1), якщо p = -0,25

Answer 1

$\displaystyle\bf\\\underbrace{(4p-1)(16p^{2} +4p+1)}_{(4p)^{3}-1^{3}}=(4p)^{3} -1^{3} =64p^{3}-1\\\\\\p=-0,25\\\\\\64p^{3}-1=64\cdot(-0,25)^{3} -1=-64\cdot 0,015625-1=\\\\=-1-1=-2$