Question

СРОЧНО НУЖНО!!!! 20 БАЛОВ ​

Answer 1

$\frac{ \sqrt{22 + 6 \sqrt{3 + \sqrt{13 + \sqrt{48} } } } }{9 + \sqrt{3} } = \frac{ \sqrt{22 + 6 \sqrt{3 + \sqrt{13 +4 \sqrt{3} } } } }{9 + \sqrt{3} } = \frac{ \sqrt{22 + 6 \sqrt{3 + \sqrt{(1 + 2 \sqrt{3} ) {}^{2} } } } }{9 + \sqrt{3} } = \frac{ \sqrt{22 + 6 \sqrt{3 +1 + 2 \sqrt{3} } } }{9 + \sqrt{3} } = \frac{ \sqrt{22 + 6 \sqrt{ {( \sqrt{3} + 1)}^{2} } } }{9 + \sqrt{3} } = \frac{ \sqrt{22 + 6( \sqrt{3 } + 1)} }{9 + \sqrt{3} } = \frac{ \sqrt{22 + 6 \sqrt{3} + 6 } }{9 + \sqrt{3} } = \frac{ \sqrt{28+ 6 \sqrt{3}} }{9 + \sqrt{3} } = \frac{ \sqrt{(1 + 3 \sqrt{3}) {}^{2} } }{9 + \sqrt{3} } = \frac{1 + 3 \sqrt{3} }{9 + \sqrt{3} } = \frac{1 + 3 \sqrt{3} }{9 + \sqrt{3} } \times \frac{9 - \sqrt{3} }{9 - \sqrt{3} } = \frac{9 - \sqrt{3} + 27 \sqrt{3} - 9}{81 - 3} = \frac{26 \sqrt{3} }{78} = \frac{ \sqrt{3} }{3}$