Question

g'(x): g(x)=3^x2-4x +log³ x+2
x-2

Answer 1

Ответ:

g(x) = 3^(x^2 - 4x) + log3(x + 2) / (x - 2)

g'(x) = [ln(3) * 3^(x^2 - 4x) * (2x - 4)] / 1 + [(1 / (x + 2) * ln(3))] / (x - 2)^2