Question

СРОЧНО! ПОМОГИТЕ ПОЖАЛУЙСТА

Answer 1

$49 {}^{ 1- log_{7}(3) } = 49 \times 49 {}^{- log_{7}(3)} = 49 \times ( {7}^{2} ) {}^{- log_{7}(3)} = 49 \times 7 {}^{-2 log_{7}(3)} = 49 \times 7 {}^{ log_{7}(3 {}^{ - 2} ) } = 49 \times 3 {}^{ - 2} = \frac{49}{9} = 5 \frac{4}{9}$