Question

пазяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяяя:c

Answer 1

$\sqrt{16a} + \sqrt{100a} - \sqrt{81a} = \sqrt{ {4}^{2}a } + \sqrt{10 {}^{2} a} - \sqrt{9 {}^{2}a } = 4 \sqrt{a} + 10 \sqrt{a} - 9 \sqrt{a} = 5 \sqrt{a}$

$( \sqrt{99} - \sqrt{77} ) \times \sqrt{11} = \sqrt{99} \times \sqrt{11} - \sqrt{77} \times \sqrt{11} = \sqrt{3 {}^{2} \times 11 {}^{2} } - \sqrt{7 \times 11 {}^{2} } = 3 \times 1 - 11 \sqrt{7} = 33 - 11 \sqrt{7}$