Question

В треугольнике ABC угол А=60° уголВ= 45° ВС = √6 найти АС

Answer 1

Ответ:

Дано : ΔABC; ∠A=60°; ∠B=45°; AC=√6 см

Найти : a = CB - ?

По теореме синусов

�

�

sin

⁡

�

=

�

sin

⁡

�

�

=

�

�

⋅

sin

⁡

�

sin

⁡

�

=

6

⋅

sin

⁡

6

0

�

sin

⁡

4

5

�

=

=

6

⋅

3

2

:

2

2

=

6

⋅

3

2

⋅

2

2

=

3

sinB

AC

=

sinA

a

a=

sinB

AC⋅sinA

=

sin45

o

6

⋅sin60

o

=

=

6

⋅

2

3

:

2

2

=

6

⋅

2

3

⋅

2

2

=3