Question

БУДЬ ЛАСКА ДОПОМОЖІТЬ З ЦИМ ЗАВДАННЯМ. СРОЧНО!!!!!! ДАЮ 50 БАЛІВ ​

Answer 1

$\displaystyle\bf\\x^{2} =\Big(\sqrt{36+10\sqrt{11} } +\sqrt{36-10\sqrt{11} }\Big)^{2} \\\\\\x^{2} =\Big(\sqrt{36+10\sqrt{11} }\Big)^{2} +2\cdot\sqrt{(36+10\sqrt{11})\cdot(36-10\sqrt{11}) }+ \Big(\sqrt{36-10\sqrt{11} }\Big)^{2} \\\\\\x^{2}=\Big|36+10\sqrt{11} \Big|+2\cdot\Big[36^{2} -(10\sqrt{11} )^{2}\Big]+\Big|36-10\sqrt{11}\Big| \\\\\\x^{2}=36+10\sqrt{11}+2\cdot(1296 -1100)+36-10\sqrt{11}\\\\\\x^{2} =72+2\cdot196\\\\\\x^{2} =464\\\\\\x_{1,2} =\pm \ \sqrt{464} =\pm \ 4\sqrt{29}$