Question

Consider a rectangular block of metal of height A, width B and length C as shown in the

figure. The block is connected to power of voltage V in two cases: in (a) case the current

through the block is IAB. Find the current in (b) case via IAB, A, B and C values.​

Answer 1

Ответ:

I = I$_{AB}$ * (C/A)^2

Объяснение:

You need to show the picture, despite it being a physics home assignment.

Main formula:

I = U/R and R = p * L/S

For the first case:

I$_{AB}$ = U / (p * C/AB) find U: U = I$_{AB}$ * (p* C/AB)

For the second case:

I = U/(p * A/BC) put U:

I = I$_{AB}$ * (p* C/AB) / (p * A/BC)

I = I$_{AB}$ * (C/A)^2

Good luck with the midterm exams.