Question

БУДЬ ЛАСКА ДОПОМОЖІТЬ!!!!!!!!!!!​

Answer 1

Ответ:

5. 1) 2√7

2) 10√3

3) 2x²√15x²

6. 1) √28

2) √44

3) √63x5

7. 1) 6√a+12√a-40√a=22√a

2) (30√2+10√2-16√2)*√2=24√2*√2=48

3) (2√3²-3√5²)=12-45=-33

Answer 2

5.

1)

$\sqrt{28} = \sqrt{4 \times 7} = 2 \sqrt{7}$

2)

$\sqrt{300} = \sqrt{100 \times 3} = 10 \sqrt{3}$

3)

$\sqrt{60 {x}^{8} } = \sqrt{4 \times 15 \times {x}^{8} } = 2 {x}^{4} \sqrt{15}$

6.

1)

$2 \sqrt{7} = \sqrt{4 \times 7} = \sqrt{28}$

2)

$2 \sqrt{11} = \sqrt{4 \times 11} = \sqrt{44}$

3)

$- 3 \sqrt{7 {x}^{5} } = - \sqrt{9 \times 7 {x}^{5} } = - \sqrt{63 {x}^{5} }$

7.

1)

$2 \sqrt{9a} + 3 \sqrt{16a} - 4 \sqrt{100a} = 6 \sqrt{a} + 12 \sqrt{a} - 40 \sqrt{a} = - 22 \sqrt{a}$

2)

$(5 \sqrt{72} + 2 \sqrt{50} - 2 \sqrt{128}) \sqrt{2} = (5 \times 6 \sqrt{2} + 2 \times 5 \sqrt{2} - 2 \times 8 \sqrt{2} ) \sqrt{2} = (30\sqrt{2} + 10\sqrt{2} - 16\sqrt{2} ) \sqrt{2} = 24 \sqrt{2} \times \sqrt{2} = 24 \times 2 = 48$

3)

$(2 \sqrt{3} - 3 \sqrt{5} )(2 \sqrt{3 + 3 \sqrt{5} } ) = {(2 \sqrt{3} })^{2} - {(3 \sqrt{5} })^{2} = 4 \times 3 - 9 \times 5 = 12 - 45 = - 33$