Question

(х+3)(2х-1)=(х+1)^2 розвязати

Answer 1

(х+3)(2х-1)=(х+1)²

2х²-х+6х-3=х²+2х+1

х²+3х-4=0

Д=3²-4×1×(-4)=9+16=25

х1=(-3+√25)/2×1=(-3+5)/2=1

х2=(-3-√25)/2×1=(-3-5)/2=-4