Question

помогите пожалуйста решить систему линейных уравнений.​

Answer 1

Объяснение:

10)

{х+у=2

{у=3х-2

{х+3х-2=2

4х=4

х=1

у=1

11){х=-у

{х-у=10

-у-у=10

-2у=10

у=-5

х=5

12)

{х=8у-7

{2х+3у=5

2(8у-7)+3у=5

16у-14+3у=5

19у=19

у=1

х=1

Answer 2

$\displaystyle\bf\\1)\\\\\left \{ {{x+y=2} \atop {y=3x-2}} \right. \\\\\\\left \{ {{x+3x-2=2} \atop {y=3x-2}} \right. \\\\\\\left \{ {{4x=4} \atop {y=3x-2}} \right. \\\\\\\left \{ {{x=1} \atop {y=3\cdot 1-2}} \right. \\\\\\\left \{ {{x=1} \atop {y=1}} \right. \\\\\\Otvet \ : \ (1 \ ; \ 1)\\\\2)\\\\\left \{ {{x=-y} \atop {x-y=10}} \right. \\\\\\\left \{ {{x=-y} \atop {-y-y=10}} \right. \\\\\\\left \{ {{x=-y} \atop {-2y=10}} \right.$

$\displaystyle\bf\\\left \{ {{x=-(-5)} \atop {y=-5}} \right. \\\\\\\left \{ {{x=5} \atop {y=-5} \right. \\\\\\Otvet \ : \ (5 \ ; \ -5)\\\\3)\\\\\left \{ {{x=8y-7} \atop {2x+3y=5}} \right.\\\\\\\left \{ {{x=8y-7} \atop {2\cdot(8y-7)+3y=5}} \right.\\\\\\\left \{ {{x=8y-7} \atop {16y-14+3y=5}} \right. \\\\\\\left \{ {{x=8y-7} \atop {19y=19}} \right. \\\\\\\left \{ {{x=8\cdot 1-7} \atop {y=1}} \right. \\\\\\\left \{ {{x=1} \atop {y=1}} \right. \\\\\\Otvet \ : \ (1 \ ; \ 1)$