Question

2) 2x-x² ≤0
Помогите

Answer 1

$2x - {x}^{2} \leqslant 0 \\ {x}^{2} - 2x \geqslant 0 \\ x(x - 2) \geqslant 0 \\ + + + + [0] - - - - [2] + + + + \\ x \: \epsilon \: ( - \infty ;0]U[2; \: + \infty )$