Question

Допомога!:>
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Answer 1

$f(x) = \frac{4}{ {x}^{ 5} } = 4 {x}^{ - 5}$

$F(x)-?$

$F(x) = \int 4 {x}^{ - 5} dx = \\ = 4 \int {x}^{ - 5} dx = \\ = 4 \times ( \frac{ {x}^{ - 5 + 1} }{ - 5 + 1} ) + C = \\ = 4 \times ( \frac{ {x}^{ - 4} }{ - 4} ) + C= \\ = 4 \times ( \frac{1}{ - 4 {x}^{4} } ) + C = \\ = - \frac{1}{ {x}^{4} } + C$

ответ: А