Question

ДОПОМОЖІТЬ ДАЮ 100 БАЛІІІВ

Answer 1

Ответ:

Пояснение:

2.

a)

$\displaystyle \\-4,3x=14,62\\\\-\frac{43}{10} x=\frac{1462}{100} \ |*100\\\\-430x=1462\ |:(-430)\\\\x=-3\frac{172}{430}=-3\frac{2*86}{5*86} =-3\frac{2}{5} =-3,4.$

Відповідь: х=-3,4.

б)

$\displaystyle \\(x+\frac{22}{25} )*\frac{1}{3} =-7\frac{1}{3} \\\\(x+\frac{22}{25})*\frac{1}{3}=-\frac{7*3+1}{3} \ |*3\\\\ x+\frac{22}{25}=-22\ |*25\\\\25x+22=-22*25\\\\25x+22=-550\\\\25x=-572\ |:25\\\\x=-22,88.$

Відповідь: х=-22,88.

3.

$14,22-25:(-6,8+4.3)=14,22-25:(-2,5)=14,22+10=24,22.$

4.

$\displaystyle \\(-3,4-6,1)*1\frac{6}{19}+(1\frac{41}{42} -2\frac{5}{21} ):1\frac{4}{7} =\\\\=-9,5*\frac{19*1+6}{19} +(\frac{42*1+41}{42} -\frac{2*41+5}{21} ):\frac{7*1+4}{7} =\\\\=-9\frac{1}{2}*\frac{25}{19}+(\frac{83}{42}-\frac{47}{21} ):\frac{11}{7}=-\frac{19}{2}*\frac{25}{19}+\frac{83-94}{42} *\frac{7}{11}=\\\\ =-\frac{25}{2} +(-\frac{11}{42} *\frac{7}{11})=-\frac{25}{2}-\frac{1}{6}=-\frac{25*3+1}{6}=-\frac{76}{6}=-12\frac{4}{6}=-12\frac{2}{3} .$

Answer 2

Ответ:

1)  Вычислить ;

$\bf a)\ \ -4,3x=14,62\ \ \Rightarrow \ \ \ x=14,62:(-4,3)\ \ ,\ \ \boxed{\bf \ x=-3,4\ }\\\\b)\ \ \Big(x+\dfrac{22}{25}\Big)\cdot \dfrac{1}{3}=-7\dfrac{1}{3}\ \ ,\ \ \ \Big(x+\dfrac{22}{25}\Big)=-\dfrac{22}{3}:\dfrac{1}{3}\ \ ,\\\\\\x+\dfrac{22}{25}=-22\ \ ,\ \ \ x=-22-\dfrac{22}{25}\ \ ,\ \ \ x=-22\dfrac{22}{25}\ \ ,\ \ \boxed{\bf \ x=-22,88\ }$          

2)  Вычислить ;

$\bf 14,22-25:(-6,8+4,3)=14,22-25:(-2,5)=14,22+10=24,22$  

3)  Выполнить действия ;

$\bf \Big(-3,4-6,1\Big)\cdot 1\dfrac{6}{19}+\Big(1\dfrac{41}{42}-2\dfrac{5}{21}\Big):1\dfrac{4}{7}=\\\\\\=-9,5\cdot \dfrac{25}{19}+\Big(\dfrac{83}{42}-\dfrac{47}{21}\Big):\dfrac{11}{7}=-\dfrac{237,5}{19}-\dfrac{11}{42}\cdot \dfrac{7}{11}=\\\\\\=-12,5-\dfrac{1}{6}=-\dfrac{25}{2}-\dfrac{1}{6}=-\dfrac{76}{6}=\boxed{\bf -12\dfrac{2}{3}\ }$