Question

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50балів​

Answer 1

По теореме Виета:

${ax}^{2} + bx + c = 0 \\ x _{1} + x_{2} = - \frac{b}{a} \\ x _{1} x_{2} = \frac{c}{a}$

1)

${x}^{2} - 6x + 5 = 0 \\ x _{1} + x_{2} = - ( - 6) = 6 \\ x _{1} x_{2} = 5$

2)

$2 {x}^{2} + 5x - 18 = 0 \\ x _{1} + x_{2} = - \frac{5}{2} = - 2.5 \\ x _{1} x_{2} = - \frac{ - 18}{2} = \frac{9}{1} = 9$