Question

СРОЧНО , ДАЮ 40 БАЛЛОВ!​

Answer 1

$a {x}^{2} + bx + c = a(x - x _{1} )(x - x_{2})\\ \\ 5 {x}^{2} - 14x - 3= 0 \\ d = ( - 14) {}^{2} - 4 \times 5 \times ( - 3) = \\ 196 + 60 = 256 \\ x _{1} = \frac{14 + 16}{5 \times 2} = \frac{30}{10} = 3 \\ x_{2} = \frac{14 - 16}{5 \times 2} = - \frac{2}{10} = - 0.2 \\ \\ 5 {x}^{2} - 14x - 3 = 5(x - 3)(x + 0.2)$