Question

алгебра 9 клас. аапрвт саити​

Answer 1

Відповідь на фото.

Успіхів

Answer 2

$\displaystyle\bf\\\frac{12-x}{x^{2} +6x} +\frac{3}{x^{2} -6x} =\frac{6}{x^{2} -36} \\\\\\\frac{12-x}{x\cdot(x +6)} +\frac{3}{x\cdot(x-6)} -\frac{6}{(x -6)(x+6)} =0\\\\\\\frac{(12-x)\cdot(x-6)+3\cdot(x+6)-6x}{x(x-6)(x+6)} =0\\\\\\\frac{12x-72-x^{2} +6x+3x+18-6x}{x(x-6)(x+6)}=0\\\\\\\frac{x^{2} -15x+54}{x(x-3)(x+3)} =0 \ \ , \ \ x\neq 0 \ , \ x\neq -3 \ ; \ x\neq 3\\\\\\x^{2} -15x+54=0\\\\D=(-15)^{2} -4\cdot 54=225-216=9=3^{2} \\\\\\x_{1} =\frac{15+3}{2} =\frac{18}{2} =9$

$\displaystyle\bf\\x_{2} =\frac{15-9}{2} =\frac{6}{2} =3- \ neyd\\\\\\Otvet \ : \ 9$