Question

x^3+x^2-4x-4=0 и другое y^3+2y^2-4y-8=0

Answer 1

1) $x^3+x^2-4x-4=0$

$x^2(x+1)-4(x+1)=0$ 

(x+1)(x-2)(x+2) =0

x = -1

x = 2

x = -2 

2) $y^3+2y^2-4y-8=0$ 

$y^2(y+2)-4(y+2)=0$ 

(y+2)(y-2)(y+2) = 0

 y = +/-2