Question

ПОМОГИТЕЕЕЕЕЕ пжжжжж ​

Answer 1

$\frac{2}{3} ( \frac{1}{3} x - \frac{1}{2} ) = 4x + 2 \frac{1}{2} \\ \frac{2}{9} x - \frac{1}{3} = 4x + 2 \frac{1}{2} \\ \frac{2}{9} x - 4x = 2 \frac{1}{2} + \frac{1}{3} \\ \frac{2}{9} x - 3 \frac{9}{9} x = 2 \frac{3}{6} + \frac{2}{6} \\ - 3 \frac{7}{9} x = 2 \frac{5}{6} \\ x = 2 \frac{5}{6} \div ( - 3 \frac{7}{9} ) \\ x = - \frac{17 \times 9}{6 \times 34} \\ x = - \frac{3}{2 \times 2} \\ x = - \frac{3}{4} \\ x = - 0.75$