Question

(х+4)*(х-2)-(4х-3)(х+5)=х(х-3)

Answer 1

Ответ:

x²-2x+4x-8-4x²-20x+3x+15=x²-3x

x²-2x+4x-8-4x²-20x+3x+15-x²+3x=0

-4x²-12x+7=0

Д= (-12)²-4*(-4)*7=144+112=256

х1= 12+√256/2*(-4)= 12+16/(-8)=28/(-8)= -3,5

х2=12-16/(-8) = -4/(-8)= 0,5