Question

4/3+19/9+82/27+...+3n×+1/3n
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Answer 1

Ответ:

a_n = (4/3) * (3/3)^(n-1) + (19/9) * (3/3)^(n-2) + (82/27) * (3/3)^(n-3) + ... + (3n+1)/(3n) * (3/3)^0

a_n = (4/3) * (3/3)^(n-1) + (19/9) * (3/3)^(n-2) + (82/27) * (3/3)^(n-3) + ... + (3n+1)/(3n)

a_n = (4/3) * (3/3)^(n-1) + (19/9) * (3/3)^(n-2) + (82/27) * (3/3)^(n-3) + ... + (3n+1)/(3n) * (3/3)^0

a_n = (4/3) * (3/3)^(n-1) + (19/9) * (3/3)^(n-2) + (82/27) * (3/3)^(n-3) + ... + (3n+1)/(3n)