Question

Помогите решить, пожалуйста

Answer 1

Ответ:

-11

Пошаговое объяснение:

$\frac{6}{x^{2} - 25} - \frac{1}{5 - x} = 0\\\frac{6}{(x - 5)(x + 5)} - \frac{1}{-(x - 5)} = 0\\\frac{6}{(x - 5)(x + 5)} + \frac{1}{x - 5} = 0\\\frac{6}{(x - 5)(x + 5)} + \frac{x + 5}{(x - 5)(x + 5)} = 0\\\frac{6 + x + 5}{(x - 5)(x + 5)} = 0\\\frac{11 + x}{(x - 5)(x + 5)} = 0\\\left \{ {{11 + x = 0} \atop {(x - 5)(x + 5) \neq 0}} \right. \\\left \{ {{x = -11} \atop {x \neq 5; x \neq -5}} \right. \\x = -11$