Question

Решите срочно уровнение пожалуйста!!

Answer 1

Ответ:

x1, y1 (-1;2)

x2, y2 (1;0)

Объяснение:

$\left \{ {{y^{2} +2x=2} \atop {x+y=1}} \right.$

$\left \{ {{y^{2}+2x=2 \atop {y=1-x} \right.$

(1-x)^2+2x=2

x= -1

x = 1

y= 1 - (-1)

y = 1-1

y = 2

y = 0

x1, y1 (-1;2)

x2, y2 (1;0)

Answer 2

$\displaystyle\bf\\\left \{ {{y^{2}+2x=2 } \atop {x+y=1}} \right. \\\\\\\left \{ {{x=1-y} \atop {y^{2} +2\cdot(1-y)=2}} \right. \\\\\\\left \{ {{x=1-y} \atop {y^{2}+2-2y-2=0}} \right. \\\\\\\left \{ {{x=1-y} \atop {y^{2} -2y=0}} \right. \\\\\\\left \{ {{x=1-y} \atop {y\cdot(y-2)=0}} \right. \\\\\\\left \{ {{x=1-y} \atop {\left[\begin{array}{ccc}y=0\\y-2=0\end{array}\right }} \right. \\\\\\\left \{ {{x=1-y} \atop {\left[\begin{array}{ccc}y_{1} =0\\y_{2} =2\end{array}\right }} \right.$

$\displaystyle\bf\\x_{1} =1-0=1\\\\x_{2} =1-2=-1\\\\\\Otvet \ : \ (1 \ ; \ 0) \ , \ (-1 \ ; \ 2)$