Question

СРОЧНО розв’яжіть рівняння

Answer 1

x ≠ 3

x ≠ - 3

$\frac{2x - 9}{ {x}^{2} - 9 } = \frac{7x - 2 {x}^{2} }{9 - {x}^{2} } \\ \frac{2x - 9}{ {x}^{2} - 9 } = - \frac{7 - 2 {x}^{2} }{ {x}^{2} - 9 } \\ 2x - 9 = - (7 - 2 {x}^{2} ) \\ 2x - 9 = - 7 + 2 {x}^{2} \\ 2 {x}^{2} - 2x - 7 + 9 = \\ 2 {x}^{2} - 2x + 2 = 0 \\ {x}^{2} - x + 1 = 0 \\ a =1 \\ b = - 1 \\ c = 1 \\ D = {b}^{2} - 4ac = ( - 1) {}^{2} - 4 \times1 \times 1 = \\ = 1 - 4 = - 3 \\ D < 0$

Ответ: нет корней