Question

Помогите остался 1 час времени!!!!!

Answer 1

$\displaystyle\bf\\x+\sqrt{x} =19\\\\\sqrt{x}=m \ \ \Rightarrow \ \ m\geq 0\\\\m^{2} +m-19=0\\\\D=1^{2}-4\cdot (-19)=1+76=77\\\\\\m_{1} =\frac{-1+\sqrt{77} }{2} \\\\\\m_{2} =\frac{-1-\sqrt{77} }{2} < 0- \ neyd\\\\\\\sqrt{x} =\frac{\sqrt{77}-1 }{2} \\\\\\x=\Big(\frac{\sqrt{77}-1 }{2}\Big)^{2} =\frac{77-2\sqrt{77} +1}{4} =\frac{78-2\sqrt{77} }{4} \\\\\\Otvet \ : \ x=\frac{78-2\sqrt{77} }{4}$

Answer 2

Решение на прикреплённой фотографии