Question

(х+3:х):2=9
Будь ласонька

Answer 1

$(x+3\div x)\div2=9\\x+3\div x=18\\\\\dfrac{x^2-18x+3}{x}=0\\ \\\text{OD3}: x\neq0\\x^2-18x+3=0\\D=(-18)^2-4\times3=324-12=312\\\\x_{1,2}=\dfrac{18\pm2\sqrt{78} }{2}=9\pm \sqrt{78}$