• Предмет: Математика
  • Автор: axezos
  • Вопрос задан 4 месяца назад

решить три примера на фотке, срочно​

Приложения:

Ответы

Ответ дал: сок111213
1

1)

1.5 \times (1 \frac{2}{3}  + 1 \frac{1}{2} ) +(2  \frac{3}{4}  - 1.25) \times (2 \frac{1}{3}  - 1.5) = 3.5 \\ 1) \: 1 \frac{2}{3}  + 1 \frac{1}{2}  = 1 \frac{4}{6}  + 1 \frac{3}{6}  = 2 \frac{7}{6}  = 3 \frac{1}{6}   \\  2) \: 1.5 \times 3 \frac{1}{6}  =  \frac{3 \times 19}{2 \times 6}  =  \frac{19}{4}  = 4 \frac{3}{4} = 4.75  \\ 3) \: 2 \frac{3}{4}  - 1.25 = 2 \frac{3}{4}  - 1 \frac{1}{4}  = 1 \frac{2}{4}  = 1 \frac{1}{2}  \\ 4) \: 2 \frac{1}{3}  - 1.5 = 2 \frac{1}{3}  - 1 \frac{1}{2}  = 2 \frac{2}{6}  - 1 \frac{3}{6}  = 1 \frac{8}{6}  - 1 \frac{3}{6}  =  \frac{5}{6}  \\ 5) \: 1 \frac{1}{2}  \times  \frac{5}{6}  =  \frac{3 \times 5}{2 \times 6}  =  \frac{5}{4}  = 1 \frac{1}{4}  = 1.25 \\ 6) \: 4.75 - 1.25 = 3.5

2)

1.8 \times (2 \frac{3}{4}  + 1 \frac{1}{3} ) + (2 \frac{3}{4}  - 0.95) \times (3 \frac{1}{4}  - 2 \frac{1}{3} ) =9  \\ 1) \: 2 \frac{3}{4}  + 1 \frac{1}{3}  =  2\frac{9}{12}  + 1 \frac{4}{12}  = 3 \frac{13}{12}  = 4 \frac{1}{12}  \\ 2) \: 1.8 \times 4 \frac{1}{12}  =  \frac{9 \times 49}{5 \times 12}  =  \frac{147}{20}  = 7 \frac{7}{20}  = 7.35 \\ 3) \: 2 \frac{3}{4}  - 0.95 = 2.75 - 0.95 = 1.8 \\ 4) \: 3 \frac{1}{4}  - 2 \frac{1}{3}  = 3 \frac{3}{12}  - 2 \frac{4}{12}  = 2 \frac{15}{12}  - 2 \frac{4}{12}  =  \frac{11}{12}  \\ 5) \: 1.8 \times  \frac{11}{12}  =  \frac{9 \times 11}{5 \times 12}  =  \frac{33}{20}  = 1 \frac{13}{20}  = 1.65 \\ 6) \:  7.35 + 1.65 = 9

3)

(2.8 \div 1 \frac{2}{5}  + 3 \frac{1}{5}  \times 1 \frac{7}{8} ) \times 10 =  80\\ 1) \: 2.8 \div 1 \frac{2}{5}  =  \frac{14 \times 5}{5 \times 7}  = 2 \\ 2) \: 3 \frac{1}{5}  \times 1 \frac{7}{8}  =  \frac{16 \times 15}{5 \times 8}  = 6 \\ 3) \: 2 + 6 = 8 \\ 4) \: 8 \times 10 = 80

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