Question

4y-5(y-x) = 8, 2(3x-y)+7y=-14;​

Answer 1

Ответ:

Объяснение:

$4y-5(y-x)=8, 2(3x-y)+7y=-14$

$\left \{ {{4y-5(y-x)=8} \atop {2(3x-y)+7=-14}} \right.$

$\left \{ {{y=-8+5x} \atop {2(3x-y)+7y=-14}} \right.$

$2(3x-(-8+5x))+7(-8+5x)=-14$

$x=\frac{26}{31}$

$y=-8+5*\frac{26}{31}$

$y=-\frac{118}{31}$

$(x,y)=(\frac{26}{31} ,- \frac{118}{31} )$

$\left \{ {{4*(-\frac{118}{31} } )-5(-\frac{118}{31} -\frac{26}{31})=8 \atop {2(3*\frac{26}{31}-(-\frac{118}{31}))+7*(-\frac{118}{31})=-14 }} \right.$

$\left \{ {{8=8} \atop {-14=-14}} \right.$

$(x,y)=(\frac{26}{31} ,-\frac{118}{31} )$