Question

помогуте пж дам 40 баллов

Answer 1

$\displaystyle\bf\\\frac{x^{2} +x-6}{x-2}=0 \\\\\\\left \{ {{x^{2} +x-6=0} \atop {x-2\neq 0}} \right. \\\\\\\left \{ {{x^{2} +x-6=0} \atop {x\neq 2}} \right. \\\\\\x^{2} +x-6=0\\\\D=1^{2} -4\cdot(-6)=1+24=25=5^{2} \\\\\\x_{1} =\frac{-1-5}{2} =\frac{-6}{2} =-3\\\\\\x_{2} =\frac{-1+5}{2} =\frac{4}{2} =2- \ ne \ podxodit\\\\\\Otvet \ : \ -3$