Question

tg3x-√3< или=0 плиз оч надо

Answer 1

$tg(3x)-sqrt{3} leq 0$
$tg(3x) leq sqrt{3}$
$-frac{pi}{2}+pi*n<3x leq frac{pi}{3}+pi*n$
$-frac{pi}{6}+frac{pi*n}{3}<x leq frac{pi}{9}+frac{pi*n}{3}$
n є Z

Answer 2

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