Question

поможіть будь ласка ​

Answer 1

$\displaystyle\bf\\\left \{ {{2 - 5x = 3(1 - y)} \atop {4(x - y) = x + 11 }} \right. \\ \displaystyle\bf\\\left \{ {{2 - 5x = 3 - 3y} \atop {4x - 4y = x + 11 }} \right. \\ \displaystyle\bf\\\left \{ {{ - 5x + 3y = 1 \: \: | \times 4} \atop {3x - 4y = 11 \: \: | \times 3}} \right. \\ \displaystyle\bf\\ +\left \{ {{ - 20x + 12y = 4} \atop {9x - 12y = 33 }} \right. \\ \\ - 20x + 9x = 33 + 4 \\ - 11x = 37 \\ x = - \frac{37}{11} \\ x = - 3 \frac{6}{11} \\ \\ - 5 \times ( - \frac{37}{11} ) + 3y = 1 \\ \frac{185}{11} + 3y = 1 \\ 3y = 1 - 16 \frac{9}{11} \\ 3y = - 15 \frac{9}{11} \\ y = - 15 \frac{9}{11} \div 3 \\ y = - \frac{174}{11 \times 3} \\ y = - \frac{58}{11} \\ y = - 5 \frac{3}{11}$

Ответ: ( - 3 6/11 ; - 5 3/11 )