Question

Розв'яжіть будь ласка, даю 30 балів. Бажано через зошит​

Answer 1

$\displaystyle\bf\\\left \{ {{\dfrac{x+3}{2} -\dfrac{y-2}{3} =2} \atop {\dfrac{x-1}{4} +\dfrac{y+1}{3}}=4 \right. \\\\\\\left \{ {{\dfrac{x+3}{2} \cdot 6-\dfrac{y-2}{3} \cdot 6=2\cdot 6} \atop {\dfrac{x-1}{4} \cdot 12+\dfrac{y+1}{3}}\cdot 12=4\cdot 12 \right. \\\\\\\left \{ {{(x+3)\cdot 3} -(y-2)\cdot2=12\atop {(x-1)\cdot 3+(y+1)\cdot 4=48}} \right. \\\\\\\left \{ {{3x+9-2y+4=12} \atop {3x-3+4y+4=48} \right. \\\\\\\left \{ {{3x-2y=-1 \ |\cdot 2} \atop {3x+4y=47}} \right.$

$\displaystyle\bf\\+\left \{ {{6x-4y=-2} \atop {3x+4y=47}} \right. \\---------\\9x=45\\\\x=45:9=5\\\\2y=3x+1=3\cdot 5+1=16\\\\y=16:2=8\\\\\\Otvet \ : \ (5 \ ; \ 8)$