Question

срочно даю 40 баллов ​

Answer 1

$\frac{48 {x}^{5} {y}^{2} }{7x {y}^{3} } = \frac{48 {x}^{4} }{7y}$

$\frac{ {y}^{2} - 3y }{ {y}^{2} - 9 } = \frac{y(y - 3)}{(y - 3)( y+ 3)} = \frac{y}{y + 3}$