Question

ТЕРМІНОВО!!!
Допоможіть з 1001 і 1002.

Answer 1

1001

$\frac{(7 - 6.35) \div 6.5 + 9.9}{(1.2 \div 36 + 1.2 \div 0.25 - 1 \frac{5}{16} ) \div \frac{169}{24} } = 20\\ 1) \: 7 - 6.35 = 0.65 \\ 2) \: 0.65 \div 6.5 = 0.1 \\ 3) \: 0.1 + 9.9 = 10 \\ 4) \: 1.2 \div 36 = \frac{12}{360} = \frac{1}{30} \\ 5) \: 1.2 \div 0.25 = 1.2 \div \frac{1}{4} = 1.2 \times 4 = 4.8 \\ 6) \: \frac{1}{30} + 4.8 = \frac{1}{30} + 4 \frac{4}{5} = \frac{1}{30} + 4 \frac{24}{30} = 4 \frac{25}{30} = 4 \frac{5}{6} \\ 7) \: 4\frac{5}{6} - 1 \frac{5}{16} = 4 \frac{40}{48} - 1 \frac{15}{48} = 3 \frac{25}{48} \\ 8) \: 3 \frac{25}{48} \div \frac{169}{24} = \frac{169 \times 24}{48 \times 169} = \frac{1}{2} \\ 9) \: 10 \div \frac{1}{2} = 10 \times 2 = 20$

1002

$(( \frac{7}{9} - \frac{47}{72} ) \div 1.25 + \frac{7}{40} ) \div (0.358 - 0.108) \times 1.6 - \frac{19}{25} = 1 \\ 1) \: \frac{7}{9} - \frac{47}{72} = \frac{56 - 47}{72} = \frac{9}{72} = \frac{1}{8} \\2 ) \: \frac{1}{8} \div 1.25 = \frac{1}{8} \div \frac{5}{4} = \frac{4}{8 \times 5} = \frac{1}{2 \times 5} = \frac{1}{10} \\ 3) \: \frac{1}{10} + \frac{7}{40} = \frac{4 + 7}{40} = \frac{11}{40} \\ 4) \: 0.358 - 0.108 = 0.25 \\ 5) \: \frac{11}{40} \div 0.25 = \frac{11}{40} \div \frac{1}{4} = \frac{11 \times 4}{40} = \frac{11}{10} \\ 6) \: \frac{11}{10} \times 1.6 = \frac{11 \times 8}{10 \times 5} = \frac{11 \times 4}{5 \times 5} = \frac{44}{25} = 1 \frac{19}{25} \\ 7) \: 1 \frac{19}{25} - \frac{19}{25} = 1$