Question

помогите пожалуйста срочно ​

Answer 1

Ответ:

1) {-2(2x-3)+2,5 = 3(y-2x)-9; y = 2,75+3/2x

-2(2x+3)+2,5 = 3(2,75+3/2x - 2x)-9

x = -11/10

y = 2,75+3/2 × (+11/10)

y = 11/10

(x,y) = (-11/10, 11/10)

{-2(2×(-11/10)+3) + 2,5 = 3(11/10 -2 × (-11/10) )-9; 4,5-4(1-(-11/10) ) = 2×11/10 - (5-(-11/10) )

{9/10 = 9/10; -39/10 = -39/10

(x,y) = (-11/10, 11/10)

2) { (x+3)²-(x-2)² = (y+2)²-(y-3)²; 13y-8x+2x² = (2+x)²+(3-x)²

{ (x+3)²-(x-2)² = (y+2)²-(y-3)²; y = 1+6/13x

(x+3)²-(x-2)² = (1+6/13x + 2)²- (1+6/13x - 3)²

x = 0

y = 1 + 6/13×0

y = 1

(x,y) = (0, 1)

{ (0+3)²-(0-2)² = (1+2)²-(1-3)²; 13×1-2×0(4-0) = (2+0)²+(3-0)²

{ 5 = 5; 13 = 13

(x,y) = (0, 1)