Question

Розвяжіть рівняння Фото Нижче

Answer 1

$\displaystyle\bf\\\frac{8}{x+3} -\frac{1}{x}=1\\\\\\\frac{8\cdot x-1\cdot(x+3)}{x\cdot (x+3)} =1\\\\\\\frac{8x-x-3}{x\cdot(x+3)} =1\\\\\\\frac{7x-3}{x\cdot(x+3)} =1\\\\\\x\cdot(x+3)=7x-3 \ \ , \ \ x\neq 0 \ \ ; \ \ x\neq -3\\\\x^{2} +3x-7x+3=0\\\\x^{2} -4x+3=0\\\\D=(-4)^{2} -4\cdot 3=16-12=4=2^{2} \\\\\\x_{1} =\frac{4-2}{2} =1\\\\\\x_{2} =\frac{4+2}{2} =3\\\\\\Otvet \ : \ 1 \ ; \ 3$