Question

(3p^2mq/2a^2b^2×3abc/8x^2y^2):9a^2b^2c^3/28pxy

Answer 1

$(frac{3p^2mq}{2a^2b^2}*frac{3abc}{8x^2y^2}):frac{9a^2b^2c^3}{28pxy}=frac{9cmp^2q}{16abx^2y^2}*frac{28pxy}{9a^2b^2c^3}=frac{7mp^3q}{4a^3b^3c^2xy}$